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Find 
lim_(x rarr-3)(x+3)/(4-sqrt(2x+22)).
Choose 1 answer:
(A) -3
(B) -4
(C) 
-(3)/(4)
(D) The limit doesn't exist

Find limx3x+342x+22 \lim _{x \rightarrow-3} \frac{x+3}{4-\sqrt{2 x+22}} .\newlineChoose 11 answer:\newline(A) 3-3\newline(B) 4-4\newline(C) 34 -\frac{3}{4} \newline(D) The limit doesn't exist

Full solution

Q. Find limx3x+342x+22 \lim _{x \rightarrow-3} \frac{x+3}{4-\sqrt{2 x+22}} .\newlineChoose 11 answer:\newline(A) 3-3\newline(B) 4-4\newline(C) 34 -\frac{3}{4} \newline(D) The limit doesn't exist
  1. Substitute x=3x = -3: First, let's try to directly substitute x=3x = -3 into the expression to see if the limit can be evaluated this way.\newlinelimx3x+342x+22\lim_{x \to -3}\frac{x+3}{4-\sqrt{2x+22}}\newline=3+342(3)+22= \frac{-3+3}{4-\sqrt{2(-3)+22}}\newline=046+22= \frac{0}{4-\sqrt{-6+22}}\newline=0416= \frac{0}{4-\sqrt{16}}\newline=04= \frac{0}{4}\newline=0= 0

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