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Which of the following could not be the lengths of the sides of a triangle?
4 in., 6 in., 8 in.

3cm,4cm,5cm

6ft,3ft,9ft

5km,2km,4km

Which of the following could not be the lengths of the sides of a triangle?\newline44 inin., 66 inin., 88 inin.\newline3 cm,4 cm,5 cm 3 \mathrm{~cm}, 4 \mathrm{~cm}, 5 \mathrm{~cm} \newline6ft,3ft,9ft 6 \mathrm{ft}, 3 \mathrm{ft}, 9 \mathrm{ft} \newline5 km,2 km,4 km 5 \mathrm{~km}, 2 \mathrm{~km}, 4 \mathrm{~km}

Full solution

Q. Which of the following could not be the lengths of the sides of a triangle?\newline44 inin., 66 inin., 88 inin.\newline3 cm,4 cm,5 cm 3 \mathrm{~cm}, 4 \mathrm{~cm}, 5 \mathrm{~cm} \newline6ft,3ft,9ft 6 \mathrm{ft}, 3 \mathrm{ft}, 9 \mathrm{ft} \newline5 km,2 km,4 km 5 \mathrm{~km}, 2 \mathrm{~km}, 4 \mathrm{~km}
  1. Check Triangle Inequality Theorem Set 11: Step 11: Check the triangle inequality theorem for the first set: 4in.4\,\text{in.}, 6in.6\,\text{in.}, 8in.8\,\text{in.}\newlineThe theorem states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.\newlineCalculation: 4in.+6in.=10in.4\,\text{in.} + 6\,\text{in.} = 10\,\text{in.}, which is greater than 8in.8\,\text{in.}; 6in.+8in.=14in.6\,\text{in.} + 8\,\text{in.} = 14\,\text{in.}, which is greater than 4in.4\,\text{in.}; 4in.+8in.=12in.4\,\text{in.} + 8\,\text{in.} = 12\,\text{in.}, which is greater than 6in.6\,\text{in.}
  2. Check Triangle Inequality Theorem Set 22: Step 22: Check the triangle inequality theorem for the second set: 3cm3\,\text{cm}, 4cm4\,\text{cm}, 5cm5\,\text{cm}. Calculation: 3cm+4cm=7cm3\,\text{cm} + 4\,\text{cm} = 7\,\text{cm}, which is greater than 5cm5\,\text{cm}; 4cm+5cm=9cm4\,\text{cm} + 5\,\text{cm} = 9\,\text{cm}, which is greater than 3cm3\,\text{cm}; 3cm+5cm=8cm3\,\text{cm} + 5\,\text{cm} = 8\,\text{cm}, which is greater than 4cm4\,\text{cm}.
  3. Check Triangle Inequality Theorem Set 33: Step 33: Check the triangle inequality theorem for the third set: 6ft6\,\text{ft}, 3ft3\,\text{ft}, 9ft9\,\text{ft}. Calculation: 6ft+3ft=9ft6\,\text{ft} + 3\,\text{ft} = 9\,\text{ft}, which is not greater than 9ft9\,\text{ft}; 3ft+9ft=12ft3\,\text{ft} + 9\,\text{ft} = 12\,\text{ft}, which is greater than 6ft6\,\text{ft}; 6ft+9ft=15ft6\,\text{ft} + 9\,\text{ft} = 15\,\text{ft}, which is greater than 3ft3\,\text{ft}.

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