Which of the equations are true identities? A. (5b-2)^(2)+4=25b^(2)-20 b B. (2x^(2)+y^(2))(2x^(2)-y^(2))=4x^(2)-y^(2) Choose 1 answer: (A) Only A (B) Only B (C) Both A and B (D) Neither A nor B

Expand (5b-2)^2: Expand (5b-2)^2 in option A. (5b-2)^2 = (5b)^2 - 2*(5b)*2 + (2)^2 = 25b^2 - 20b + 4Compare with option A: Compare the expanded form of (5b-2)^2 + 4 with the right side of option A. 25b^2 - 20b + 4 + 4 = 25b^2 - 20b + 8, which is not equal to 25b^2 - 20b.Option A evaluation: Option A is not a true identity because the left side does not equal the right side.Expand (2x^2 + y^2)(2x^2 - y^2): Expand (2x^2 + y^2)(2x^2 - y^2) in option B using the difference of squares formula. (2x^2 + y^2)(2x^2 - y^2) = (2x^2)^2 - (y^2)^2 = 4x^4 - y^4Compare with option B: Compare the expanded form of (2x^2 + y^2)(2x^2 - y^2) with the right side of option B. 4x^4 - y^4 is not equal to 4x^2 - y^2.

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Which of the equations are true identities?
A.
(5b-2)^(2)+4=25b^(2)-20 b
B.
(2x^(2)+y^(2))(2x^(2)-y^(2))=4x^(2)-y^(2)
Choose 1 answer:
(A) Only A
(B) Only B
(C) Both A and B
(D) Neither
A nor
B

Which of the equations are true identities? $\newline$ A. $(5 b-2)^{2}+4=25 b^{2}-20 b$ $\newline$ B. $\left(2 x^{2}+y^{2}\right)\left(2 x^{2}-y^{2}\right)=4 x^{2}-y^{2}$ $\newline$ Choose $1$ answer: $\newline$ (A) Only A $\newline$ (B) Only B $\newline$ (C) Both A and B $\newline$ (D) Neither $\mathrm{A}$ nor $\mathrm{B}$

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Math Problems

Calculus

Find derivatives of using multiple formulae

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Q. Which of the equations are true identities?

\newline

(5 b-2)^{2}+4=25 b^{2}-20 b

\newline

\left(2 x^{2}+y^{2}\right)\left(2 x^{2}-y^{2}\right)=4 x^{2}-y^{2}

\newline

Choose

1

answer:

\newline

(A) Only A

\newline

(B) Only B

\newline

\newline

(D) Neither

\mathrm{A}

nor

\mathrm{B}

Expand $(5b-2)^2$ : Expand $(5b-2)^2$ in option A. $\newline$ $(5b-2)^2 = (5b)^2 - 2\cdot(5b)\cdot2 + (2)^2 = 25b^2 - 20b + 4$
Compare with option A: Compare the expanded form of $(5b-2)^2 + 4$ with the right side of option A. $25b^2 - 20b + 4 + 4 = 25b^2 - 20b + 8$ , which is not equal to $25b^2 - 20b$ .
Option A evaluation: Option A is not a true identity because the left side does not equal the right side.
Expand $(2x^2 + y^2)(2x^2 - y^2)$ : Expand $(2x^2 + y^2)(2x^2 - y^2)$ in option B using the difference of squares formula. $\newline$ $(2x^2 + y^2)(2x^2 - y^2) = (2x^2)^2 - (y^2)^2 = 4x^4 - y^4$
Compare with option B: Compare the expanded form of $(2x^2 + y^2)(2x^2 - y^2)$ with the right side of option B. $4x^4 - y^4$ is not equal to $4x^2 - y^2$ .