What is the modulus (absolute value) of -6+4i ? Don't round. If necessary, express your answer as a radical. |-6+4i|=

Calculate modulus of complex number: The modulus of a complex number a + bi is given by the square root of the sum of the squares of its real part (a) and its imaginary part (b). In this case, the complex number is -6 + 4i, so we need to calculate the square root of (-6)^2 + (4)^2.Square the real part: First, we square the real part: (-6)^2 = 36.Square the imaginary part: Next, we square the imaginary part: (4)^2 = 16.Add squares of real and imaginary parts: Now, we add the squares of the real and imaginary parts: 36 + 16 = 52.Take square root of sum: Finally, we take the square root of the sum to find the modulus: √52. Since 52 is not a perfect square, we leave the answer as a radical.

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What is the modulus (absolute value) of
-6+4i ?
Don't round. If necessary, express your answer as a radical.

|-6+4i|=

What is the modulus (absolute value) of $-6+4 i$ ? $\newline$ Don't round. If necessary, express your answer as a radical. $\newline$ $|-6+4 i|=$

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Algebra 1

Transformations of absolute value functions: translations and reflections

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Q. What is the modulus (absolute value) of

-6+4 i

\newline

Don't round. If necessary, express your answer as a radical.

\newline

|-6+4 i|=

Calculate modulus of complex number: The modulus of a complex number $a + bi$ is given by the square root of the sum of the squares of its real part ( $a$ ) and its imaginary part ( $b$ ). In this case, the complex number is $-6 + 4i$ , so we need to calculate the square root of $(-6)^2 + (4)^2$ .
Square the real part: First, we square the real part: $(-6)^2 = 36$ .
Square the imaginary part: Next, we square the imaginary part: $(4)^2 = 16$ .
Add squares of real and imaginary parts: Now, we add the squares of the real and imaginary parts: $36 + 16 = 52$ .
Take square root of sum: Finally, we take the square root of the sum to find the modulus: $\sqrt{52}$ . Since $52$ is not a perfect square, we leave the answer as a radical.