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What is the center of the ellipse x2+15y2−90=0x^2 + 15y^2 - 90 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Q. What is the center of the ellipse x2+15y2−90=0x^2 + 15y^2 - 90 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Divide by 9090: Divide the entire equation by 9090 to get the standard form of the ellipse equation.\newlinex290+15y290=9090\frac{x^2}{90} + \frac{15y^2}{90} = \frac{90}{90}\newlinex290+y26=1\frac{x^2}{90} + \frac{y^2}{6} = 1
  2. Identify center: Identify the center of the ellipse by comparing the equation to the standard form (x−h)2/a2+(y−k)2/b2=1(x-h)^2/a^2 + (y-k)^2/b^2 = 1. Since there are no (h,k)(h, k) terms, the center is at (0,0)(0, 0).

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