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What is the center of the ellipse 9x2+y2−18=09x^2 + y^2 - 18 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Q. What is the center of the ellipse 9x2+y2−18=09x^2 + y^2 - 18 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Divide by 1818: Divide both sides of the equation by 1818 to get the standard form of the ellipse equation.\newline(9x2)/18+(y2)/18=18/18(9x^2)/18 + (y^2)/18 = 18/18\newlineSimplify the fractions.\newlinex2/2+y2/18=1x^2/2 + y^2/18 = 1
  2. Simplify fractions: Identify the center of the ellipse from the standard form.\newlineThe standard form of an ellipse is (x−h)2/a2+(y−k)2/b2=1(x-h)^2/a^2 + (y-k)^2/b^2 = 1, where (h,k)(h, k) is the center.\newlineHere, the equation is already in the form (x−0)2/22+(y−0)2/182=1(x-0)^2/2^2 + (y-0)^2/18^2 = 1.\newlineSo, the center is (0,0)(0, 0).

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