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What is the center of the ellipse 6x2+y2−18=06x^2 + y^2 - 18 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Q. What is the center of the ellipse 6x2+y2−18=06x^2 + y^2 - 18 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Divide by 1818: Divide both sides of the equation by 1818 to get the standard form of the ellipse equation.\newlinex23+y218=1\frac{x^2}{3} + \frac{y^2}{18} = 1
  2. Identify center: Identify the center of the ellipse by comparing the standard form to x-h)^\(2/a^22 + (y-k)^22/b^22 = 11. The center h, k) is at \(\(0, 00) since there are no \(h) and \(k) values subtracted from \(x) and \(y) in the equation.

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