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What is the center of the ellipse 4x2+7y2−84=04x^2 + 7y^2 - 84 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Q. What is the center of the ellipse 4x2+7y2−84=04x^2 + 7y^2 - 84 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Divide and Simplify: Now, divide the entire equation by 8484 to get the standard form of the ellipse.\newline4x284+7y284=8484 \frac{4x^2}{84} + \frac{7y^2}{84} = \frac{84}{84} \newlineSimplify the fractions.\newlinex2/21+y2/12=1 x^2/21 + y^2/12 = 1
  2. Identify Center: Identify the center of the ellipse by comparing it to the standard form (x−h)2/a2+(y−k)2/b2=1(x-h)^2/a^2 + (y-k)^2/b^2 = 1. Here, hh and kk are both 00, so the center is at (0,0)(0, 0).

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