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What is the center of the ellipse 2x2+19y2−38=02x^2 + 19y^2 - 38 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Q. What is the center of the ellipse 2x2+19y2−38=02x^2 + 19y^2 - 38 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Divide and Simplify: Now, divide the entire equation by 3838 to get the standard form of the ellipse equation.\newline2x238+19y238=3838 \frac{2x^2}{38} + \frac{19y^2}{38} = \frac{38}{38} \newlineSimplify the fractions.\newlinex2/19+y2/2=1 x^2/19 + y^2/2 = 1
  2. Identify Center: Identify the center of the ellipse by comparing it to the standard form (x−h)2/a2+(y−k)2/b2=1(x-h)^2/a^2 + (y-k)^2/b^2 = 1. Since there are no (h,k)(h, k) terms, the center is at (0,0)(0, 0).

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