Q. Using implicit differentiation, find dxdy.xy=−5+yx3
Apply Implicit Differentiation: First, we need to apply implicit differentiation to both sides of the equation with respect to x. The equation is xy=−5+yx3. We will differentiate term by term.
Differentiate Left Side: Differentiate the left side, xy, with respect to x. Using the chain rule, we get 21(xy)−21×(xdxdy+y).
Differentiate Right Side: Differentiate the right side, −5+yx3, with respect to x. The derivative of −5 is 0, and using the product rule for yx3, we get 3yx2+x3(dxdy).
Equate Derivatives: Now we equate the derivatives from the left and right sides to get (21)(xy)−21∗(xdxdy+y)=3yx2+x3dxdy.
Solve for dxdy: We need to solve for dxdy. To do this, we'll collect all the terms containing dxdy on one side and the rest on the other side. This gives us 21(xy)−21⋅xdxdy−x3dxdy=3yx2−21(xy)−21⋅y.
Factor Out (dxdy): Factor out (dxdy) from the terms on the left side to get (\frac{dy}{dx})((\frac{\(1\)}{\(2\)})(xy)^{-\frac{\(1\)}{\(2\)}} \cdot x - x^\(3) = 3yx^2 - (\frac{1}{2})(xy)^{-\frac{1}{2}} \cdot y.
Isolate (dxdy):</b>Dividebothsidesby$(21(xy)−21⋅x−x3) to isolate (dxdy). This gives us (\frac{dy}{dx}) = \frac{\(3\)yx^\(2\) - \left(\frac{\(1\)}{\(2\)}(xy)^{-\frac{\(1\)}{\(2\)}} \cdot y\right)}{\left(\frac{\(1\)}{\(2\)}(xy)^{-\frac{\(1\)}{\(2\)}} \cdot x - x^\(3\)\right)}.}
Simplify \((\frac{dy}{dx}): Simplify the expression for \$(\frac{dy}{dx}) if possible. However, in this case, the expression is already in its simplest form, so we have our final answer.
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