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Simplify.
Multiply and remove all perfect squares from inside the square roots. Assume 
b is positive.

2sqrt(8b^(3))*9sqrt(18 b)=

Simplify.\newlineMultiply and remove all perfect squares from inside the square roots. Assume \newlineb b is positive.\newline28b3918b= 2\sqrt{8b^{3}} \cdot 9\sqrt{18b} =

Full solution

Q. Simplify.\newlineMultiply and remove all perfect squares from inside the square roots. Assume \newlineb b is positive.\newline28b3918b= 2\sqrt{8b^{3}} \cdot 9\sqrt{18b} =
  1. Factor the numbers: Factor the numbers inside the square roots to reveal any perfect squares.\newlineWe have 28b3×918b2\sqrt{8b^3} \times 9\sqrt{18b}. Let's factor 88 and 1818 to find perfect squares.\newline8=238 = 2^3 and 18=2×3218 = 2 \times 3^2.\newlineSo, 8b3=23×b38b^3 = 2^3 \times b^3 and 18b=2×32×b18b = 2 \times 3^2 \times b.
  2. Rewrite the expression: Rewrite the expression using the factors found.\newlineNow we can rewrite the expression as:\newline223b39232b2\sqrt{2^3 \cdot b^3} \cdot 9\sqrt{2 \cdot 3^2 \cdot b}.
  3. Simplify the square roots: Simplify the square roots by taking out the perfect squares.\newlineWe can take the square root of any perfect squares inside the square roots:\newline2222b2b2\sqrt{2^2 \cdot 2 \cdot b^2 \cdot b} 9232b\cdot 9\sqrt{2 \cdot 3^2 \cdot b}\newline= 22b2b2 \cdot 2 \cdot b \cdot \sqrt{2b} 93b\cdot 9 \cdot 3 \cdot \sqrt{b}\newline= 4b2b4b \cdot \sqrt{2b} 27b\cdot 27 \cdot \sqrt{b}.
  4. Combine the constants and square roots: Combine the constants and the square roots.\newlineNow we multiply the constants together and the square roots together:\newline(4b×27)×(2b×b)(4b \times 27) \times (\sqrt{2b} \times \sqrt{b})\newline=108b×2b2= 108b \times \sqrt{2b^2}\newline=108b×2×b2= 108b \times \sqrt{2 \times b^2}.
  5. Simplify the square root: Simplify the square root by taking out the perfect square b2b^2.\newlineSince b2b^2 is a perfect square, we can take bb out of the square root:\newline108bb2108b \cdot b \cdot \sqrt{2}\newline= 108b22108b^2 \cdot \sqrt{2}.

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