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Roselyn is driving to visit her family, who live 150 kilometers away. Her average speed is 60 kilometers per hour. The car's tank has 20 liters of fuel at the beginning of the drive, and its fuel efficiency is 6 kilometers per liter. Fuel costs 0.60 dollars per liter.
How long can Roselyn drive before she runs out of fuel?
hours

Roselyn is driving to visit her family, who live $150$ kilometers away. Her average speed is $60$ kilometers per hour. The car's tank has $20$ liters of fuel at the beginning of the drive, and its fuel efficiency is $6$ kilometers per liter. Fuel costs $0.60$ dollars per liter. $\newline$ How long can Roselyn drive before she runs out of fuel? $\newline$ hours

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Multi-step problems with unit conversions

Full solution

Q. Roselyn is driving to visit her family, who live

150

kilometers away. Her average speed is

60

kilometers per hour. The car's tank has

20

liters of fuel at the beginning of the drive, and its fuel efficiency is

6

kilometers per liter. Fuel costs

0.60

dollars per liter.

\newline

How long can Roselyn drive before she runs out of fuel?

\newline

hours

Calculate total distance: Calculate the total distance Roselyn can drive with the fuel she has. $\newline$ Fuel efficiency is given as $6$ kilometers per liter, and she has $20$ liters of fuel. $\newline$ Total distance $=$ Fuel efficiency $\times$ Amount of fuel $\newline$ Total distance $=$ $6 \, \text{km/liter} \times 20 \, \text{liters}$
Perform calculation: Perform the calculation from Step $1$ . $\newline$ Total distance = $6 \frac{\text{km}}{\text{liter}} \times 20 \text{liters} = 120 \text{kilometers}$ $\newline$ Roselyn can drive $120$ kilometers before she runs out of fuel.
Calculate time: Calculate the time it will take for Roselyn to drive the total distance before running out of fuel. $\newline$ We know her average speed is $60$ kilometers per hour. $\newline$ Time $=$ Total distance $/$ Average speed $\newline$ Time $=$ $120$ kilometers $/$ $60$ kilometers per hour
Perform calculation: Perform the calculation from Step $3$ . $\newline$ Time = $\frac{120 \text{ kilometers}}{60 \text{ kilometers per hour}} = 2 \text{ hours}$ $\newline$ Roselyn can drive for $2$ hours before she runs out of fuel.

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