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Let’s check out your problem:
Use the following function rule to find
f
(
1
)
f(1)
f
(
1
)
.
\newline
f
(
x
)
=
5
x
+
1
f(x) = 5^x + 1
f
(
x
)
=
5
x
+
1
\newline
f
(
1
)
=
f(1) =
f
(
1
)
=
_____
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Math Problems
Algebra 2
Evaluate exponential functions
Full solution
Q.
Use the following function rule to find
f
(
1
)
f(1)
f
(
1
)
.
\newline
f
(
x
)
=
5
x
+
1
f(x) = 5^x + 1
f
(
x
)
=
5
x
+
1
\newline
f
(
1
)
=
f(1) =
f
(
1
)
=
_____
Identify Function:
Identify the function which represents
f
(
1
)
f(1)
f
(
1
)
.
\newline
Substitute in
1
1
1
for
x
x
x
in
f
(
x
)
=
5
x
+
1
f(x) = 5^x + 1
f
(
x
)
=
5
x
+
1
.
\newline
f
(
1
)
=
5
1
+
1
f(1) = 5^1 + 1
f
(
1
)
=
5
1
+
1
Substitute in
1
1
1
:
Evaluate
5
1
5^1
5
1
.
\newline
5
1
=
5
5^1 = 5
5
1
=
5
Evaluate
5
1
5^1
5
1
:
f
(
1
)
=
5
+
1
f(1) = 5 + 1
f
(
1
)
=
5
+
1
\newline
Determine the value of
f
(
1
)
f(1)
f
(
1
)
.
\newline
f
(
1
)
=
5
+
1
f(1) = 5 + 1
f
(
1
)
=
5
+
1
\newline
f
(
1
)
=
6
f(1) = 6
f
(
1
)
=
6
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\newline
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\newline
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The graph of a sinusoidal function intersects its midline at
(
0
,
−
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)
(0,-7)
(
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,
−
7
)
and then has a minimum point at
(
π
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,
−
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Write the formula of the function, where
x
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f
(
x
)
=
f(x)=
f
(
x
)
=
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The following formula is used in economics to find a company's gross profit rate
P
P
P
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S
S
S
is the net sales and
C
C
C
is the cost of goods sold.
\newline
P
=
S
−
C
S
P=\frac{S-C}{S}
P
=
S
S
−
C
\newline
Rearrange the formula to highlight the cost of goods sold.
\newline
C
=
□
C=\square
C
=
□
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Posted 10 months ago
Question
3
⋅
5
0.2
w
=
720
3 \cdot 5^{0.2 w}=720
3
⋅
5
0.2
w
=
720
\newline
What is the solution of the equation?
\newline
Round your answer, if necessary, to the nearest thousandth.
\newline
w
≈
w \approx
w
≈
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Question
18
⋅
2
5
t
=
261
18 \cdot 2^{5 t}=261
18
⋅
2
5
t
=
261
\newline
What is the solution of the equation?
\newline
Round your answer, if necessary, to the nearest thousandth.
\newline
t
≈
t \approx
t
≈
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Question
−
4
⋅
3
6
w
=
−
1750
-4 \cdot 3^{6 w}=-1750
−
4
⋅
3
6
w
=
−
1750
\newline
What is the solution of the equation?
\newline
Round your answer, if necessary, to the nearest thousandth.
\newline
w
≈
w \approx
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≈
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20
⋅
7
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y
=
5
20 \cdot 7^{3 y}=5
20
⋅
7
3
y
=
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\newline
What is the solution of the equation?
\newline
Round your answer, if necessary, to the nearest thousandth.
\newline
y
≈
y \approx
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Question
10
⋅
3
5
t
4
=
800
10 \cdot 3^{\frac{5 t}{4}}=800
10
⋅
3
4
5
t
=
800
\newline
What is the solution of the equation?
\newline
Round your answer, if necessary, to the nearest thousandth.
\newline
t
≈
t \approx
t
≈
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