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The warming or cooling rate of a drink is proportional to the difference between the ambient temperature 
T_(a) and the current temperature 
T of the drink.
Which equation describes this relationship?
Choose 1 answer:
(A) 
T(t)=k(T_(a)-T)
(B) 
(dT)/(dt)=k(T_(a)-T)
(C) 
(dT)/(dt)=(k)/((T_(a)-T))
(D) 
T(t)=(k)/((T_(a)-T))

The warming or cooling rate of a drink is proportional to the difference between the ambient temperature Ta T_{a} and the current temperature T T of the drink.\newlineWhich equation describes this relationship?\newlineChoose 11 answer:\newline(A) T(t)=k(TaT) T(t)=k\left(T_{a}-T\right) \newline(B) dTdt=k(TaT) \frac{d T}{d t}=k\left(T_{a}-T\right) \newline(C) dTdt=k(TaT) \frac{d T}{d t}=\frac{k}{\left(T_{a}-T\right)} \newline(D) T(t)=k(TaT) T(t)=\frac{k}{\left(T_{a}-T\right)}

Full solution

Q. The warming or cooling rate of a drink is proportional to the difference between the ambient temperature Ta T_{a} and the current temperature T T of the drink.\newlineWhich equation describes this relationship?\newlineChoose 11 answer:\newline(A) T(t)=k(TaT) T(t)=k\left(T_{a}-T\right) \newline(B) dTdt=k(TaT) \frac{d T}{d t}=k\left(T_{a}-T\right) \newline(C) dTdt=k(TaT) \frac{d T}{d t}=\frac{k}{\left(T_{a}-T\right)} \newline(D) T(t)=k(TaT) T(t)=\frac{k}{\left(T_{a}-T\right)}
  1. Understand the problem: Understand the problem.\newlineThe problem states that the rate of change of the temperature of the drink with respect to time dTdt\frac{dT}{dt} is proportional to the difference between the ambient temperature TaT_a and the current temperature of the drink TT. This is a statement of a rate of change, which is a derivative with respect to time.
  2. Translate into equation: Translate the problem into a mathematical equation.\newlineSince the rate of change of the temperature is proportional to the difference in temperatures, we can express this as an equation involving a derivative. The constant of proportionality is represented by kk. The equation should therefore be of the form:\newlinedTdt=k×(TaT)\frac{dT}{dt} = k \times (T_a - T)
  3. Match with options: Match the equation with the given options.\newlineWe are looking for an equation that represents the rate of change of the temperature dTdt\frac{dT}{dt} being proportional to the difference TaTT_a - T. The correct equation must have the derivative dTdt\frac{dT}{dt} on one side and the expression involving the difference in temperatures on the other side, multiplied by the constant kk.
  4. Identify correct option: Identify the correct option.\newlineOption (A) T(t)=k(TaT)T(t) = k(T_a - T) does not have the derivative form we are looking for.\newlineOption (B) dTdt=k(TaT)\frac{dT}{dt} = k(T_a - T) matches the form we derived in Step 22.\newlineOption (C) dTdt=kTaT\frac{dT}{dt} = \frac{k}{T_a - T} has the derivative form but the relationship is not proportional, it is inversely proportional.\newlineOption (D) T(t)=kTaTT(t) = \frac{k}{T_a - T} does not have the derivative form and also represents an inverse proportionality.\newlineThe correct option is (B) because it correctly represents the rate of change of the temperature being proportional to the difference in temperatures.

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