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The surface area of a sphere is increasing at a rate of $14 \pi$ square meters per hour.$\newline$At a certain instant, the surface area is $36 \pi$ square meters.$\newline$What is the rate of change of the volume of the sphere at that instant (in cubic meters per hour)?$\newline$Choose $1$ answer:$\newline$(A) $36 \pi$$\newline$(B) $(\sqrt{14 \pi})^{3}$$\newline$(C) $21 \pi$$\newline$(D) $\frac{7}{12}$$\newline$The surface area of a sphere with radius $r$ is $4 \pi r^{2}$.$\newline$The volume of a sphere with radius $r$ is $\frac{4}{3} \pi r^{3}$.