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The second derivative of a function 
h is given by 
h^('')(x)=(root(3)(x))/(e^(x))+1.
Where does the graph of 
h have a point of inflection?
Use a graphing calculator.
Choose 1 answer:
(A) 
x=-0.35
(B) 
x=0
(C) 
x=0.33
(D) 
x=1.497

The second derivative of a function h h is given by h(x)=x3ex+1 h^{\prime \prime}(x)=\frac{\sqrt[3]{x}}{e^{x}}+1 .\newlineWhere does the graph of h h have a point of inflection?\newlineUse a graphing calculator.\newlineChoose 11 answer:\newline(A) x=0.35 x=-0.35 \newline(B) x=0 x=0 \newline(C) x=0.33 x=0.33 \newline(D) x=1.497 x=1.497

Full solution

Q. The second derivative of a function h h is given by h(x)=x3ex+1 h^{\prime \prime}(x)=\frac{\sqrt[3]{x}}{e^{x}}+1 .\newlineWhere does the graph of h h have a point of inflection?\newlineUse a graphing calculator.\newlineChoose 11 answer:\newline(A) x=0.35 x=-0.35 \newline(B) x=0 x=0 \newline(C) x=0.33 x=0.33 \newline(D) x=1.497 x=1.497
  1. Set Second Derivative Equal: To find the point of inflection, we need to set the second derivative equal to zero and solve for xx.h(x)=x3ex+1=0h''(x) = \frac{\sqrt[3]{x}}{e^{x}} + 1 = 0
  2. Use Graphing Calculator: We use a graphing calculator to find the value of xx where h(x)=0h''(x) = 0.
  3. Find XX-Value: After plotting the function h(x)h''(x) on the graphing calculator, we look for the xx-value where the graph crosses the xx-axis.
  4. Crosses X-Axis: The graph crosses the x-axis near x=1.497x = 1.497, which corresponds to answer choice (D).

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