The radius of a cone is increasing at a rate of 3 centimeters per second and the height of the cone is decreasing at a rate of 4 centimeters per second.At a certain instant, the radius is 8 centimeters and the height is 10 centimeters.What is the rate of change of the volume of the cone at that instant (in cubic centimeters per second)?Choose 1 answer:(A) 3224π(B) −3224π(C) −3736π(D) 3736πThe volume of a cone with radius r and height h is πr23h.
Q. The radius of a cone is increasing at a rate of 3 centimeters per second and the height of the cone is decreasing at a rate of 4 centimeters per second.At a certain instant, the radius is 8 centimeters and the height is 10 centimeters.What is the rate of change of the volume of the cone at that instant (in cubic centimeters per second)?Choose 1 answer:(A) 3224π(B) −3224π(C) −3736π(D) 3736πThe volume of a cone with radius r and height h is πr23h.
Volume of Cone Formula: The formula for the volume of a cone is V=31πr2h. We need to find dtdV, the rate of change of the volume.
Chain Rule Application: To find dtdV, we use the chain rule: dtdV=drdV⋅dtdr+dhdV⋅dtdh.
Calculate dV/dr: First, we find dV/dr. Since V=(1/3)πr2h, dV/dr=(2/3)πrh.
Calculate dhdV: Next, we find dhdV. Since V=31πr2h, dhdV=31πr2.
Find dtdr and dtdh: Now we plug in the values for dtdr and dtdh. We know dtdr=3cm/s and dtdh=−4cm/s.
Substitute Values: We also plug in the values for r and h at the instant we are considering. r=8 cm and h=10 cm.
Calculate dtdV: Now we calculate dtdV=(32)πrh⋅dtdr+(31)πr2⋅dtdh.
Substitute Known Values: Substitute the known values: dtdV=(32)π(8cm)(10cm)×3cm/s+(31)π(8cm)2×(−4cm/s).
Simplify Expression: Simplify the expression: dtdV=(32)π(80 cm2)×3 cm/s+(31)π(64 cm2)×(−4 cm/s).
Perform Calculations: Perform the calculations: dtdV=(32)π(240 cm3/s)+(31)π(−256 cm3/s).
Combine Terms: Combine the terms: dtdV=(32)π(240 cm3/s)−(31)π(256 cm3/s).
Final Result:dtdV=160πcm3/s−85.333πcm3/s.
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