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The lion population in a certain reserve drops by 
5% every year. Currently, the population's size is 200.
Write a function that gives the lion population size, 
P(t), 
t years from today.

P(t)=◻++x__

The lion population in a certain reserve drops by 5% 5 \% every year. Currently, the population's size is 200200.\newlineWrite a function that gives the lion population size, P(t) P(t) , t t years from today.\newlineP(t)= P(t)=\square

Full solution

Q. The lion population in a certain reserve drops by 5% 5 \% every year. Currently, the population's size is 200200.\newlineWrite a function that gives the lion population size, P(t) P(t) , t t years from today.\newlineP(t)= P(t)=\square
  1. Exponential Decay Function: Step 11: To model a population that decreases by a certain percentage each year, we use an exponential decay function. The general form of an exponential decay function is P(t)=P0×(1r)tP(t) = P_0 \times (1 - r)^t, where P0P_0 is the initial population size, rr is the decay rate as a decimal, and tt is the time in years.
  2. Initial Population and Decay Rate: Step 22: The initial population size, P0P_0, is given as 200200 lions. The annual decay rate is 5%5\%, which as a decimal is 0.050.05. Therefore, the decay factor is 1r1 - r, which is 10.05=0.951 - 0.05 = 0.95.
  3. Substitute Values into Function: Step 33: Substitute the values of P0P_0 and the decay factor into the exponential decay function to get the function for the lion population size. P(t)=200×0.95tP(t) = 200 \times 0.95^t.
  4. Check Population Decrease: Step 44: Check the function to ensure it represents a decreasing population over time. If tt increases, the term 0.95t0.95^t decreases because 0.950.95 is less than 11, which means the population size P(t)P(t) will also decrease. This aligns with the given information that the population drops by 5%5\% each year.

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