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The equation for line pp can be written as y=12x+8y = -\frac{1}{2}x + 8. Line qq, which is perpendicular to line pp, includes the point (4,7)(4,7). What is the equation of line qq?\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.

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Q. The equation for line pp can be written as y=12x+8y = -\frac{1}{2}x + 8. Line qq, which is perpendicular to line pp, includes the point (4,7)(4,7). What is the equation of line qq?\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.
  1. Perpendicular Lines Slopes: Line qq is perpendicular to line pp. Are their slopes the same or opposite reciprocals?\newlineSlopes of perpendicular lines are opposite reciprocals.
  2. Equation of Line p: Equation of line p: y=12x+8y = -\frac{1}{2}x + 8\newlineFind the slope of line p.\newlineCompare y=12x+8y = -\frac{1}{2}x + 8 with y=mx+by = mx + b.\newlinem=12m = -\frac{1}{2}\newlineSlope of line p: 12-\frac{1}{2}
  3. Slope of Line q: Line q is perpendicular to p.\newlineSlope of line p: 12-\frac{1}{2}\newlineFind the slope of line q.\newlineOpposite reciprocal of 12-\frac{1}{2} is 22.\newlineSlope of line q: 22
  4. Finding Y-Intercept: For line qq:\newlineSlope (mm): 22\newlinePoint: (4,7)(4, 7)\newlinePlug these values in y=mx+by = mx + b and find the y-intercept.\newline7=2(4)+b7 = 2(4) + b\newline7=8+b7 = 8 + b\newline78=b7 - 8 = b\newline1=b-1 = b
  5. Equation of Line q: For line q:\newlineSlope mm: 22\newliney-intercept bb: 1-1\newlineWhat is the equation of the line q in slope-intercept form?\newlineSubstitute 22 for mm and 1-1 for bb in y=mx+by = mx + b.\newliney=2x1y = 2x - 1

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