The base of a solid is the region enclosed by the graphs of y=2+2x and y=22x, between the y-axis and x=4.Cross sections of the solid perpendicular to the x-axis are rectangles whose height is 4−x.Which one of the definite integrals gives the volume of the solid?Choose 1 answer:(A) ∫04[2+2x−22x](4−x)dx(B) ∫04[22x+2x+2](4−x)dx(C) ∫04[22x−2x−2](4−x)dx(D) ∫04[22x−2x+2](4−x)dx
Q. The base of a solid is the region enclosed by the graphs of y=2+2x and y=22x, between the y-axis and x=4.Cross sections of the solid perpendicular to the x-axis are rectangles whose height is 4−x.Which one of the definite integrals gives the volume of the solid?Choose 1 answer:(A) ∫04[2+2x−22x](4−x)dx(B) ∫04[22x+2x+2](4−x)dx(C) ∫04[22x−2x−2](4−x)dx(D) ∫04[22x−2x+2](4−x)dx
Identify Volume Calculation: To find the volume of the solid, we need to integrate the area of the cross sections along the x-axis from x=0 to x=4. The area of each cross section is given by the difference in the y-values of the two functions times the height of the rectangle (4−x).
Find Difference in Y-values: First, we need to find the difference in the y-values of the two functions y=2+(x/2) and y=2(x/2). This difference will be the length of the base of the rectangle for the cross section at each point x. Difference in y-values: (2+(x/2))−2(x/2)
Calculate Area of Cross Section: Now, we multiply the difference in y-values by the height of the rectangle (4−x) to get the area of the cross section at each point x.Area of cross section: [2+(2x)−2(2x)]×(4−x)
Integrate Area for Volume: To find the volume of the solid, we integrate the area of the cross sections from x=0 to x=4. Volume of solid: ∫04[(2+(x/2))−2(x/2)]⋅(4−x)dx
Match Answer Choices: Looking at the answer choices, we see that option (A) matches our expression for the volume of the solid.Final answer: (A)∫04[2+(x/2)−2(x/2)]∗(4−x)dx
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