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The average cost per meal served at Kiran's restaurant decreases at a rate of 
(2400)/(q^(2)) dollars per meal served that month (where 
q is the number of meals served).
By how many dollars does the average cost per meal decrease between 
q=300 and 
q=360 ?
Choose 1 answer:
(A) 0.67
(B) 0.81
(C) 1.11
(D) 1.33

The average cost per meal served at Kiran's restaurant decreases at a rate of 2400q2 \frac{2400}{q^{2}} dollars per meal served that month (where q q is the number of meals served).\newlineBy how many dollars does the average cost per meal decrease between q=300 q=300 and q=360 q=360 ?\newlineChoose 11 answer:\newline(A) 00.6767\newline(B) 00.8181\newline(C) 11.1111\newline(D) 11.3333

Full solution

Q. The average cost per meal served at Kiran's restaurant decreases at a rate of 2400q2 \frac{2400}{q^{2}} dollars per meal served that month (where q q is the number of meals served).\newlineBy how many dollars does the average cost per meal decrease between q=300 q=300 and q=360 q=360 ?\newlineChoose 11 answer:\newline(A) 00.6767\newline(B) 00.8181\newline(C) 11.1111\newline(D) 11.3333
  1. Understand and Identify: Understand the problem and identify the given information.\newlineWe are given the rate at which the average cost per meal decreases as a function of the number of meals served, which is 2400q2\frac{2400}{q^2} dollars per meal. We need to find the decrease in the average cost per meal between q=300q=300 and q=360q=360.
  2. Calculate at q=300q=300: Calculate the average cost per meal decrease at q=300q=300. Using the given rate of decrease, we find the average cost per meal decrease at q=300q=300 by substituting q=300q=300 into the rate function: Decrease at q=300q=300 = 24003002\frac{2400}{300^2} dollars per meal.
  3. Calculation at q=300q=300: Perform the calculation for the decrease at q=300q=300.
    Decrease at q=300q=300 = 24003002\frac{2400}{300^2} = 240090000\frac{2400}{90000} = 0.0266660.026666\dots dollars per meal.
  4. Calculate at q=360q=360: Calculate the average cost per meal decrease at q=360q=360. Using the given rate of decrease, we find the average cost per meal decrease at q=360q=360 by substituting q=360q=360 into the rate function: Decrease at q=360q=360 = 2400(3602)\frac{2400}{(360^2)} dollars per meal.
  5. Calculation at q=360q=360: Perform the calculation for the decrease at q=360q=360.\newlineDecrease at q=360q=360 = 24003602\frac{2400}{360^2} = 2400129600\frac{2400}{129600} = 0.01851850.0185185... dollars per meal.
  6. Calculate Difference: Calculate the difference in the average cost per meal decrease between q=300q=300 and q=360q=360.\newlineDifference = Decrease at q=300q=300 - Decrease at q=360q=360.
  7. Calculation for Difference: Perform the calculation for the difference.\newlineDifference = 0.026666...0.0185185...=0.008148...0.026666... - 0.0185185... = 0.008148... dollars per meal.
  8. Round the Result: Round the result to two decimal places to match the answer choices. Difference 0.008\approx 0.008 dollars per meal, which is the same as 0.810.81 cents per meal.
  9. Match with Answer Choices: Match the result with the given answer choices.\newlineThe result 0.810.81 cents per meal corresponds to answer choice (B) 0.810.81.

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