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Solve using substitution.\newline7x2y=7-7x - 2y = 7\newlinex=1x = 1\newline(_____, _____)

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Q. Solve using substitution.\newline7x2y=7-7x - 2y = 7\newlinex=1x = 1\newline(_____, _____)
  1. Substitute xx value: Substitute the value of xx into the first equation.\newlineWe are given x=1x = 1, so we can substitute this value into the first equation to find yy.\newline7(1)2y=7–7(1) − 2y = 7
  2. Simplify and solve for y: Simplify the equation and solve for y. \newline72y=7-7 - 2y = 7\newlineAdd 77 to both sides to isolate the term with y.\newline7+72y=7+7-7 + 7 - 2y = 7 + 7\newline02y=140 - 2y = 14\newline2y=14-2y = 14
  3. Divide to find yy: Divide both sides by 2-2 to find the value of yy.2y2=142\frac{-2y}{-2} = \frac{14}{-2}y=7y = -7
  4. Write as ordered pair: Write the solution as an ordered pair.\newlineSince x=1x = 1 and y=7y = -7, the solution to the system of equations is (1,7)(1, -7).

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