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Solve for
y :

{:[y-(-10)=-41],[y=◻]:}

Solve for $y$ : $\newline$ $\begin{array}{l} y-(-10)=-41 \\ y=\square \end{array}$

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Solve multi-step inequalities

Full solution

Q. Solve for

y

:

\newline

\begin{array}{l} y-(-10)=-41 \\ y=\square \end{array}

Isolate variable y: Isolate the variable $y$ in the first equation $y - (-10) = -41$ . $\newline$ $y - (-10) = -41$ $\newline$ $y + 10 = -41$
Subtract $10$ : Subtract $10$ from both sides to solve for $y$ . $\newline$ $y + 10 - 10 = -41 - 10$ $\newline$ $y = -51$
Check solution: Check the solution by substituting $y = -51$ into the first equation.\(\newline\)( $-51$ ) - ( $-10$ ) = $-41$ \(\newline\) $-51$ + $10$ = $-41$ \(\newline\) $-41$ = $-41$
Conclude solution: Since the second part of the system is simply $y$ equals a value, and we have found $y = -51$ , we can conclude that the solution to the system is $y = -51$ .

More problems from Solve multi-step inequalities

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Question

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Sean's justification:

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Is Issac's justification complete? If not, why?

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Issac's justification:

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\begin{array}{l} f(1.5)=0 \text { and } \\ f(2)=1 \text {, so } \\ f(1.5)<0.1<f(2) . \end{array}

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Question

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Below is Bridget's attempt to write a formal justification for the fact that the equation

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Is Bridget's justification complete? If not, why?

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Bridget's justification:

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Ibrahim's justification:

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Amrita's justification:

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Polynomial and trigonometric functions are differentiable and continuous at all points in their domain, and

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Is Omar's justification complete? If not, why?

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Omar's justification:

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Is Lena's justification complete? If not, why?

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Lena's justification:

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f(0)=0

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So, according to the mean value theorem,

f^{\prime}(x)=\frac{2}{3}

must have a solution somewhere in the interval

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1

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(A) Yes, Lena's justification is complete.

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(B) No, Lena didn't establish that the average rate of change of

f

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(C) No, Lena didn't establish that

f

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h(x)=3^{x}-x^{2}

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Below is Uriah's attempt to write a formal justification for the fact that the equation

h^{\prime}(x)=8

has a solution where

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Is Uriah's justification complete? If not, why?

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Uriah's justification:

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Polynomial and exponential functions are differentiable and continuous at all points in their domain, and

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1

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(B) No, Uriah didn't establish that the average rate of change of

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