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solve for xx cosx+sinx=2\cos x +\sin x = \sqrt{2}

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Q. solve for xx cosx+sinx=2\cos x +\sin x = \sqrt{2}
  1. Recognize Equality Condition: Recognize that cos(x)\cos(x) and sin(x)\sin(x) are equal when xx is 4545 degrees or π4\frac{\pi}{4} radians.
  2. Use Trigonometric Identity: Use the identity sin(x)=cos(π2x)\sin(x) = \cos(\frac{\pi}{2} - x) to rewrite the equation as cos(x)+cos(π2x)=2\cos(x) + \cos(\frac{\pi}{2} - x) = \sqrt{2}.
  3. Substitute xx Value: Since cos(x)=cos(π2x)\cos(x) = \cos(\frac{\pi}{2} - x) when x=π4x = \frac{\pi}{4}, substitute π4\frac{\pi}{4} into the equation to check if it satisfies the equation.
  4. Calculate Cosine and Sine: Calculate cos(π4)+sin(π4)\cos(\frac{\pi}{4}) + \sin(\frac{\pi}{4}) and see if it equals 2\sqrt{2}.\newlinecos(π4)=22\cos(\frac{\pi}{4}) = \frac{\sqrt{2}}{2} and sin(π4)=22.\sin(\frac{\pi}{4}) = \frac{\sqrt{2}}{2}.
  5. Add Values: Add the values: 2/2+2/2=2\sqrt{2}/2 + \sqrt{2}/2 = \sqrt{2}.
  6. Verify Solution: Since the sum equals 2\sqrt{2}, x=π4x = \frac{\pi}{4} is a solution.

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