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Select the outlier in the data set.\newline9,38,40,42,43,44,52,609, 38, 40, 42, 43, 44, 52, 60\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline9,38,40,42,43,44,52,609, 38, 40, 42, 43, 44, 52, 60\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 9,38,40,42,43,44,52,609, 38, 40, 42, 43, 44, 52, 60\newlineTo find the outlier, look for a number that is significantly different from the rest. Here, 99 stands out as much lower than the other numbers.
  2. Calculate Mean with Outlier: Step 22: Calculate the mean of the data set including the outlier.\newlineMean = 9+38+40+42+43+44+52+608\frac{9 + 38 + 40 + 42 + 43 + 44 + 52 + 60}{8}\newlineMean = 3288\frac{328}{8}\newlineMean = 4141
  3. Calculate Mean without Outlier: Step 33: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (38+40+42+43+44+52+60)/7(38 + 40 + 42 + 43 + 44 + 52 + 60) / 7\newlineMean without outlier = 319/7319 / 7\newlineMean without outlier = 45.5745.57
  4. Compare Mean Changes: Step 44: Compare the two means to determine if the mean increases or decreases when the outlier is removed.\newlineSince 45.5745.57 (mean without outlier) is greater than 4141 (mean with outlier), removing the outlier increases the mean.

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