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Select the outlier in the data set.\newline84,85,87,88,89,90,92,54484, 85, 87, 88, 89, 90, 92, 544\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline84,85,87,88,89,90,92,54484, 85, 87, 88, 89, 90, 92, 544\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set: 84,85,87,88,89,90,92,54484, 85, 87, 88, 89, 90, 92, 544. An outlier is a data point that is significantly different from the rest of the data. In this case, 544544 stands out as it is much larger than the other numbers.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included.\newlineMean = (84+85+87+88+89+90+92+544)/8(84 + 85 + 87 + 88 + 89 + 90 + 92 + 544) / 8\newlineMean = (1059)/8(1059) / 8\newlineMean = 132.375132.375
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (84+85+87+88+89+90+92)/7(84 + 85 + 87 + 88 + 89 + 90 + 92) / 7\newlineMean without outlier = (615)/7(615) / 7\newlineMean without outlier = 87.857187.8571 (rounded to 44 decimal places)
  4. Compare Mean Changes: Compare the two means to determine if the mean would increase or decrease upon the removal of the outlier. The mean without the outlier (87.857187.8571) is less than the mean with the outlier (132.375132.375), so the mean would decrease if the outlier were removed.

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