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Select the outlier in the data set.\newline8,82,84,85,87,92,94,96,998, 82, 84, 85, 87, 92, 94, 96, 99\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline8,82,84,85,87,92,94,96,998, 82, 84, 85, 87, 92, 94, 96, 99\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 8,82,84,85,87,92,94,96,998, 82, 84, 85, 87, 92, 94, 96, 99.\newlineOutliers are values that are much smaller or larger than the rest of the data. Here, 88 is much smaller than all other values.
  2. Calculate Mean with Outlier: Step 22: Calculate the mean of the data set including the outlier.\newlineMean = (8+82+84+85+87+92+94+96+99)/9(8 + 82 + 84 + 85 + 87 + 92 + 94 + 96 + 99) / 9\newlineMean = 727/9727 / 9\newlineMean = 80.7880.78
  3. Calculate Mean without Outlier: Step 33: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (82+84+85+87+92+94+96+99)/8(82 + 84 + 85 + 87 + 92 + 94 + 96 + 99) / 8\newlineMean without outlier = 719/8719 / 8\newlineMean without outlier = 89.8889.88
  4. Compare Mean Changes: Step 44: Compare the two means to determine if the mean increases or decreases when the outlier is removed.\newlineOriginal mean: 80.7880.78\newlineMean without outlier: 89.8889.88\newlineSince 89.8889.88 is greater than 80.7880.78, removing the outlier increases the mean.

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