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Select the outlier in the data set.\newline8,70,72,75,80,82,87,89,948, 70, 72, 75, 80, 82, 87, 89, 94\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline8,70,72,75,80,82,87,89,948, 70, 72, 75, 80, 82, 87, 89, 94\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set: 8,70,72,75,80,82,87,89,948, 70, 72, 75, 80, 82, 87, 89, 94. To find the outlier, we can use the interquartile range (IQR) method or simply look for a number that is significantly different from the rest of the data.
  2. Observation: By observation, the number 88 stands out as significantly lower than the rest of the data points. The rest of the numbers are all 7070 or higher, which suggests that 88 is the outlier.
  3. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included:\newlineMean = (8+70+72+75+80+82+87+89+94)/9(8 + 70 + 72 + 75 + 80 + 82 + 87 + 89 + 94) / 9\newlineMean = (657)/9(657) / 9\newlineMean = 7373
  4. Calculate Mean without Outlier: Calculate the mean of the data set with the outlier removed:\newlineMean without outlier = (70+72+75+80+82+87+89+94)/8(70 + 72 + 75 + 80 + 82 + 87 + 89 + 94) / 8\newlineMean without outlier = (649)/8(649) / 8\newlineMean without outlier = 81.12581.125
  5. Compare Mean: Compare the two means to determine if the mean would increase or decrease with the removal of the outlier:\newlineMean with outlier = 7373\newlineMean without outlier = 81.12581.125\newlineSince 81.12581.125 is greater than 7373, the mean would increase if the outlier were removed.

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