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Select the outlier in the data set.\newline7,79,85,89,90,92,94,987, 79, 85, 89, 90, 92, 94, 98\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline7,79,85,89,90,92,94,987, 79, 85, 89, 90, 92, 94, 98\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set: 7,79,85,89,90,92,94,987, 79, 85, 89, 90, 92, 94, 98. An outlier is a data point that is significantly different from the rest of the data. We can visually inspect the data set and see that 77 is much lower than all other numbers, which are close to each other and in the range of 7979 to 9898.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included.\newlineMean = (7+79+85+89+90+92+94+98)/8(7 + 79 + 85 + 89 + 90 + 92 + 94 + 98) / 8\newlineMean = (634)/8(634) / 8\newlineMean = 79.2579.25
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier 77.\newlineMean without outlier = (79+85+89+90+92+94+98)/7(79 + 85 + 89 + 90 + 92 + 94 + 98) / 7\newlineMean without outlier = (627)/7(627) / 7\newlineMean without outlier = 89.5789.57 (rounded to two decimal places)
  4. Compare Mean Changes: Compare the two means to determine if the mean would increase or decrease upon the removal of the outlier. The mean without the outlier (89.5789.57) is greater than the mean with the outlier (79.2579.25). Therefore, removing the outlier would increase the mean.

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