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Select the outlier in the data set.\newline62,72,78,82,83,86,87,97,41262, 72, 78, 82, 83, 86, 87, 97, 412\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline62,72,78,82,83,86,87,97,41262, 72, 78, 82, 83, 86, 87, 97, 412\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 62,72,78,82,83,86,87,97,41262, 72, 78, 82, 83, 86, 87, 97, 412\newlineLooking at the numbers, 412412 stands out significantly from the rest, which are all below 100100.
  2. Calculate Mean: Step 22: Calculate the mean of the original data set.\newlineMean = (62+72+78+82+83+86+87+97+412)/9(62 + 72 + 78 + 82 + 83 + 86 + 87 + 97 + 412) / 9\newlineMean = 1059/91059 / 9\newlineMean = 117.67117.67
  3. Remove Outlier: Step 33: Remove the outlier 412412 and calculate the new mean.\newlineNew data set: 62,72,78,82,83,86,87,9762, 72, 78, 82, 83, 86, 87, 97\newlineNew Mean = (62+72+78+82+83+86+87+97)/8(62 + 72 + 78 + 82 + 83 + 86 + 87 + 97) / 8\newlineNew Mean = 647/8647 / 8\newlineNew Mean = 80.87580.875
  4. Compare Means: Step 44: Compare the original mean and the new mean to determine if the mean increased or decreased.\newlineOriginal Mean = 117.67117.67, New Mean = 80.87580.875\newlineSince the new mean is less than the original mean, removing the outlier decreased the mean.

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