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Select the outlier in the data set.\newline60,70,78,80,84,86,93,95,60960, 70, 78, 80, 84, 86, 93, 95, 609\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline60,70,78,80,84,86,93,95,60960, 70, 78, 80, 84, 86, 93, 95, 609\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set.\newlineThe data set is: 60,70,78,80,84,86,93,95,60960, 70, 78, 80, 84, 86, 93, 95, 609.\newlineAn outlier is a data point that is significantly different from the rest of the data. In this case, 609609 is much larger than all other values, which are relatively close to each other. Therefore, 609609 is the outlier.
  2. Calculate Mean with Outlier: Calculate the mean of the data set including the outlier.\newlineTo find the mean, add all the numbers together and divide by the number of data points.\newlineMean = (60+70+78+80+84+86+93+95+609)/9(60 + 70 + 78 + 80 + 84 + 86 + 93 + 95 + 609) / 9\newlineMean = (1255)/9(1255) / 9\newlineMean ≈139.44\approx 139.44
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineRemove the outlier 609609 and calculate the new mean.\newlineNew Mean = (60+70+78+80+84+86+93+95)/8(60 + 70 + 78 + 80 + 84 + 86 + 93 + 95) / 8\newlineNew Mean = (646)/8(646) / 8\newlineNew Mean = 80.7580.75
  4. Compare Means: Compare the means to determine if the mean would increase or decrease upon removal of the outlier. The original mean with the outlier was approximately 139.44139.44, and the new mean without the outlier is 80.7580.75. Since the new mean is lower than the original mean, removing the outlier would decrease the mean.

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