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Select the outlier in the data set.\newline6,66,68,70,71,73,75,79,876, 66, 68, 70, 71, 73, 75, 79, 87\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline6,66,68,70,71,73,75,79,876, 66, 68, 70, 71, 73, 75, 79, 87\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 6,66,68,70,71,73,75,79,876, 66, 68, 70, 71, 73, 75, 79, 87\newlineOutliers are numbers that are significantly different from the others. Here, 66 is much lower than all other numbers.
  2. Calculate Mean with Outlier: Step 22: Calculate the mean of the data set including the outlier.\newlineMean = 6+66+68+70+71+73+75+79+879\frac{6 + 66 + 68 + 70 + 71 + 73 + 75 + 79 + 87}{9}\newlineMean = 5959\frac{595}{9}\newlineMean = 66.1166.11
  3. Calculate Mean without Outlier: Step 33: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (66+68+70+71+73+75+79+87)/8(66 + 68 + 70 + 71 + 73 + 75 + 79 + 87) / 8\newlineMean without outlier = 589/8589 / 8\newlineMean without outlier = 73.62573.625
  4. Compare Mean Changes: Step 44: Compare the two means to determine if the mean increases or decreases when the outlier is removed.\newlineSince 73.62573.625 (without outlier) is greater than 66.1166.11 (with outlier), removing the outlier increases the mean.

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