Select the outlier in the data set. 6, 44, 50, 52, 53, 58, 60, 69 If the outlier were removed from the data set, would the mean increase or decrease? Choices: (A)increase (B)decrease

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Select the outlier in the data set. 6, 44, 50, 52, 53, 58, 60, 69  If the outlier were removed from the data set, would the mean increase or decrease?   Choices: (A)increase (B)decrease

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Identify Outlier: Identify the outlier in the given data set: 6, 44, 50, 52, 53, 58, 60, 69. To find the outlier, we can calculate the interquartile range (IQR) and then determine if any values fall more than 1.5 times the IQR above the third quartile or below the first quartile.Arrange Data: First, arrange the data set in ascending order, which is already done: 6, 44, 50, 52, 53, 58, 60, 69. Next, find the median (the middle value) of the data set. Since there are 8 numbers, the median will be the average of the 4th and 5th values: (52 + 53) / 2 = 52.5.Find Median: Now, find the first quartile (Q1), which is the median of the first half of the data set: 6, 44, 50, 52. The median of these four numbers is (44 + 50) / 2 = 47.Find Q1: Find the third quartile (Q3), which is the median of the second half of the data set: 53, 58, 60, 69. The median of these four numbers is (58 + 60) / 2 = 59.Find Q3: Calculate the interquartile range (IQR): IQR = Q3 - Q1 = 59 - 47 = 12.Calculate IQR: Determine the lower bound for potential outliers: Q1 - 1.5 * IQR = 47 - 1.5 * 12 = 47 - 18 = 29. Determine the upper bound for potential outliers: Q3 + 1.5 * IQR = 59 + 1.5 * 12 = 59 + 18 = 77. Any number below 29 or above 77 is considered an outlier.Determine Lower Bound: Looking at the data set, the number 6 is below the lower bound of 29, so it is an outlier. There are no numbers above the upper bound of 77.Determine Upper Bound: Now, let's determine if the mean would increase or decrease upon the removal of the outlier 6. First, calculate the mean of the original data set: (6 + 44 + 50 + 52 + 53 + 58 + 60 + 69) / 8 = 392 / 8 = 49.Identify Outlier Removal: Next, calculate the mean of the data set without the outlier 6: (44 + 50 + 52 + 53 + 58 + 60 + 69) / 7 = 386 / 7 ≈ 55.14.Calculate Mean Original: Comparing the two means, the mean without the outlier 6 is greater than the mean with the outlier. Therefore, the mean would increase if the outlier were removed.

Select the outlier in the data set. $\newline$ $6, 44, 50, 52, 53, 58, 60, 69$ $\newline$ If the outlier were removed from the data set, would the mean increase or decrease? $\newline$ Choices: $\newline$ (A)increase $\newline$ (B)decrease

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Select the outlier in the data set.\newline6,44,50,52,53,58,60,696, 44, 50, 52, 53, 58, 60, 696,44,50,52,53,58,60,69\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

Select the outlier in the data set. $\newline$ $6, 44, 50, 52, 53, 58, 60, 69$ $\newline$ If the outlier were removed from the data set, would the mean increase or decrease? $\newline$ Choices: $\newline$ (A)increase $\newline$ (B)decrease