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Select the outlier in the data set.\newline52,62,70,71,80,82,83,93,97452, 62, 70, 71, 80, 82, 83, 93, 974\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline52,62,70,71,80,82,83,93,97452, 62, 70, 71, 80, 82, 83, 93, 974\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 52,62,70,71,80,82,83,93,97452, 62, 70, 71, 80, 82, 83, 93, 974.\newlineLooking at the numbers, 974974 stands out as it is much higher than the rest of the values.
  2. Calculate Mean with Outlier: Step 22: Calculate the mean of the data set including the outlier.\newlineMean = (52+62+70+71+80+82+83+93+974)/9(52 + 62 + 70 + 71 + 80 + 82 + 83 + 93 + 974) / 9\newlineMean = (1667)/9(1667) / 9\newlineMean = 185.22185.22
  3. Calculate Mean without Outlier: Step 33: Calculate the mean of the data set without the outlier.\newlineMean without 974974 = (52+62+70+71+80+82+83+93)/8(52 + 62 + 70 + 71 + 80 + 82 + 83 + 93) / 8\newlineMean = (593)/8(593) / 8\newlineMean = 74.12574.125
  4. Compare Mean Changes: Step 44: Compare the two means to determine if the mean increases or decreases when the outlier is removed.\newlineMean with outlier = 185.22185.22\newlineMean without outlier = 74.12574.125\newlineSince 185.22185.22 is greater than 74.12574.125, removing the outlier decreases the mean.

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