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Select the outlier in the data set.\newline51,61,63,66,70,76,77,83,38651, 61, 63, 66, 70, 76, 77, 83, 386\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline51,61,63,66,70,76,77,83,38651, 61, 63, 66, 70, 76, 77, 83, 386\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set.\newlineThe data set is: 51,61,63,66,70,76,77,83,38651, 61, 63, 66, 70, 76, 77, 83, 386\newlineAn outlier is a data point that is significantly different from the rest of the data. In this case, 386386 stands out as it is much higher than the other values.
  2. Calculate Mean with Outlier: Calculate the mean of the data set including the outlier.\newlineMean = (51+61+63+66+70+76+77+83+386)/9(51 + 61 + 63 + 66 + 70 + 76 + 77 + 83 + 386) / 9\newlineMean = (933)/9(933) / 9\newlineMean = 103.67103.67 (rounded to two decimal places)
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (51+61+63+66+70+76+77+83)/8(51 + 61 + 63 + 66 + 70 + 76 + 77 + 83) / 8\newlineMean without outlier = (547)/8(547) / 8\newlineMean without outlier = 68.37568.375
  4. Compare Means: Compare the means to determine if the mean would increase or decrease upon removal of the outlier. The mean with the outlier is 103.67103.67, and the mean without the outlier is 68.37568.375. Removing the outlier would decrease the mean.

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