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Select the outlier in the data set.\newline50,60,66,67,73,74,76,88,67450, 60, 66, 67, 73, 74, 76, 88, 674\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline50,60,66,67,73,74,76,88,67450, 60, 66, 67, 73, 74, 76, 88, 674\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set.\newlineThe data set is: 50,60,66,67,73,74,76,88,67450, 60, 66, 67, 73, 74, 76, 88, 674.\newlineAn outlier is a data point that is significantly different from the rest of the data. In this case, 674674 is much larger than all other numbers in the set.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included.\newlineMean = (50+60+66+67+73+74+76+88+674)/9(50 + 60 + 66 + 67 + 73 + 74 + 76 + 88 + 674) / 9\newlineMean = (1228+674)/9(1228 + 674) / 9\newlineMean = 1902/91902 / 9\newlineMean ≈211.33\approx 211.33
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (50+60+66+67+73+74+76+88)/8(50 + 60 + 66 + 67 + 73 + 74 + 76 + 88) / 8\newlineMean without outlier = 554/8554 / 8\newlineMean without outlier = 69.2569.25
  4. Compare Mean Changes: Compare the means to determine if the mean would increase or decrease with the removal of the outlier. The mean with the outlier is approximately 211.33211.33, and the mean without the outlier is 69.2569.25. Removing the outlier significantly decreases the mean.

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