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Select the outlier in the data set.\newline50,57,73,80,93,96,98,62950, 57, 73, 80, 93, 96, 98, 629\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline50,57,73,80,93,96,98,62950, 57, 73, 80, 93, 96, 98, 629\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify the Outlier: Identify the outlier in the given data set.\newlineThe data set is: 50,57,73,80,93,96,98,62950, 57, 73, 80, 93, 96, 98, 629.\newlineAn outlier is a data point that is significantly different from the other data points in a set. We can often spot an outlier by looking for a number that is much higher or lower than the rest of the numbers in the set.\newlineIn this case, 629629 is much higher than all the other numbers, so it is the outlier.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included.\newlineTo find the mean, add all the numbers together and then divide by the number of data points.\newlineMean = (50+57+73+80+93+96+98+629)/8(50 + 57 + 73 + 80 + 93 + 96 + 98 + 629) / 8\newlineMean = (1176+629)/8(1176 + 629) / 8\newlineMean = 1805/81805 / 8\newlineMean = 225.625225.625
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineTo find the new mean, subtract the outlier from the previous total and then divide by the new number of data points (77 instead of 88).\newlineNew Mean = (1805629)/7(1805 - 629) / 7\newlineNew Mean = 1176/71176 / 7\newlineNew Mean = 168168
  4. Compare Means: Compare the two means to determine if the mean would increase or decrease with the removal of the outlier. The original mean with the outlier was 225.625225.625, and the new mean without the outlier is 168168. Since 168168 is less than 225.625225.625, the mean would decrease if the outlier were removed.

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