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Select the outlier in the data set.\newline50,57,65,66,67,68,69,71,35650, 57, 65, 66, 67, 68, 69, 71, 356\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline50,57,65,66,67,68,69,71,35650, 57, 65, 66, 67, 68, 69, 71, 356\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set.\newlineThe data set is: 50,57,65,66,67,68,69,71,35650, 57, 65, 66, 67, 68, 69, 71, 356.\newlineAn outlier is a value that is significantly higher or lower than the rest of the data. In this case, 356356 stands out as it is much higher than the other values.
  2. Calculate Mean with Outlier: Calculate the mean of the data set including the outlier.\newlineTo find the mean, add all the numbers together and divide by the number of values.\newlineMean = (50+57+65+66+67+68+69+71+356)/9(50 + 57 + 65 + 66 + 67 + 68 + 69 + 71 + 356) / 9\newlineMean = (799)/9(799) / 9\newlineMean ≈88.78\approx 88.78
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineRemove the outlier 356356 and calculate the new mean.\newlineMean without outlier = (50+57+65+66+67+68+69+71)/8(50 + 57 + 65 + 66 + 67 + 68 + 69 + 71) / 8\newlineMean without outlier = (513)/8(513) / 8\newlineMean without outlier ≈64.13\approx 64.13
  4. Compare Means: Compare the means to determine if the mean would increase or decrease upon removal of the outlier. The original mean with the outlier was approximately 88.7888.78, and the mean without the outlier is approximately 64.1364.13. Removing the outlier significantly decreases the mean.

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