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Select the outlier in the data set.\newline5,63,73,75,79,83,89,975, 63, 73, 75, 79, 83, 89, 97\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline5,63,73,75,79,83,89,975, 63, 73, 75, 79, 83, 89, 97\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set: 5,63,73,75,79,83,89,975, 63, 73, 75, 79, 83, 89, 97. To find the outlier, we can look for a number that is significantly different from the rest of the data. In this case, 55 is much lower than all other numbers, which are all above 6060.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included: (5+63+73+75+79+83+89+97)/8(5 + 63 + 73 + 75 + 79 + 83 + 89 + 97) / 8. Perform the addition: 5+63+73+75+79+83+89+97=5645 + 63 + 73 + 75 + 79 + 83 + 89 + 97 = 564. Now divide by 88: 564/8=70.5564 / 8 = 70.5. The mean with the outlier is 70.570.5.
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier: (63+73+75+79+83+89+97)/7(63 + 73 + 75 + 79 + 83 + 89 + 97) / 7. Perform the addition: 63+73+75+79+83+89+97=55963 + 73 + 75 + 79 + 83 + 89 + 97 = 559. Now divide by 77: 559/7=79.857559 / 7 = 79.857. The mean without the outlier is approximately 79.85779.857.
  4. Compare Means: Compare the two means to determine if the mean would increase or decrease upon the removal of the outlier. The mean with the outlier is 70.570.5, and the mean without the outlier is approximately 79.85779.857. Since 79.85779.857 is greater than 70.570.5, the mean would increase if the outlier were removed.

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