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Select the outlier in the data set.\newline42,52,62,67,68,71,84,94,54842, 52, 62, 67, 68, 71, 84, 94, 548\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline42,52,62,67,68,71,84,94,54842, 52, 62, 67, 68, 71, 84, 94, 548\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set: 42,52,62,67,68,71,84,94,54842, 52, 62, 67, 68, 71, 84, 94, 548. To find the outlier, we can look for a number that is significantly different from the rest of the data points.
  2. Find Outlier: Looking at the data set, we can see that 548548 is much larger than all other numbers, which are relatively close to each other. Therefore, 548548 is the outlier.
  3. Calculate Mean with Outlier: Now, let's calculate the mean of the data set with the outlier included.\newlineMean = (42+52+62+67+68+71+84+94+548)/9(42 + 52 + 62 + 67 + 68 + 71 + 84 + 94 + 548) / 9\newlineMean = (1088)/9(1088) / 9\newlineMean ≈120.89\approx 120.89
  4. Calculate Mean without Outlier: Next, calculate the mean of the data set without the outlier.\newlineMean without outlier = (42+52+62+67+68+71+84+94)/8(42 + 52 + 62 + 67 + 68 + 71 + 84 + 94) / 8\newlineMean without outlier = (540)/8(540) / 8\newlineMean without outlier = 67.567.5
  5. Compare Means: Compare the two means to determine if the mean would increase or decrease upon the removal of the outlier. The mean with the outlier is approximately 120.89120.89, and the mean without the outlier is 67.567.5. Removing the outlier decreases the mean.

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