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Select the outlier in the data set.\newline42,52,58,76,85,94,96,45942, 52, 58, 76, 85, 94, 96, 459\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline42,52,58,76,85,94,96,45942, 52, 58, 76, 85, 94, 96, 459\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 42,52,58,76,85,94,96,45942, 52, 58, 76, 85, 94, 96, 459\newlineTo find the outlier, look for a number that is significantly different from the rest.\newline459459 is much higher than all other numbers.
  2. Calculate Mean with Outlier: Step 22: Calculate the mean of the data set including the outlier.\newlineMean = (42+52+58+76+85+94+96+459)/8(42 + 52 + 58 + 76 + 85 + 94 + 96 + 459) / 8\newlineMean = 962/8962 / 8\newlineMean = 120.25120.25
  3. Calculate Mean without Outlier: Step 33: Calculate the mean of the data set without the outlier.\newlineMean without 459=(42+52+58+76+85+94+96)/7459 = (42 + 52 + 58 + 76 + 85 + 94 + 96) / 7\newlineMean without 459=503/7459 = 503 / 7\newlineMean without 459=71.86459 = 71.86
  4. Compare Mean with and without Outlier: Step 44: Compare the two means to determine if the mean increases or decreases when the outlier is removed.\newlineMean with outlier = 120.25120.25\newlineMean without outlier = 71.8671.86\newlineSince 120.25 > 71.86, removing the outlier decreases the mean.

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