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Select the outlier in the data set.\newline37,44,48,49,50,51,55,70937, 44, 48, 49, 50, 51, 55, 709\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline37,44,48,49,50,51,55,70937, 44, 48, 49, 50, 51, 55, 709\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier by looking for a number that is significantly different from the rest of the data.\newlineLooking at the data set: 37,44,48,49,50,51,55,70937, 44, 48, 49, 50, 51, 55, 709, it's clear that 709709 is way higher than all other numbers.
  2. Confirm Outlier: Confirm that 709709 is the outlier by comparing it to the rest of the data set.\newlineAll other numbers are within a range of 3737 to 5555, so 709709 is the outlier.
  3. Calculate Mean with Outlier: Calculate the mean of the original data set with the outlier.\newlineMean = (37+44+48+49+50+51+55+709)/8(37 + 44 + 48 + 49 + 50 + 51 + 55 + 709) / 8\newlineMean = 993/8993 / 8\newlineMean = 124.125124.125
  4. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (37+44+48+49+50+51+55)/7(37 + 44 + 48 + 49 + 50 + 51 + 55) / 7\newlineMean without outlier = 334/7334 / 7\newlineMean without outlier = 47.71428571428571547.714285714285715
  5. Compare Means: Compare the two means to determine if the mean would increase or decrease after removing the outlier. Since 124.125124.125 (with outlier) is greater than 47.71428571428571547.714285714285715 (without outlier), removing the outlier will decrease the mean.

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