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Select the outlier in the data set.\newline36,45,59,60,67,73,77,91136, 45, 59, 60, 67, 73, 77, 911\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline36,45,59,60,67,73,77,91136, 45, 59, 60, 67, 73, 77, 911\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set.\newlineThe data set is: 36,45,59,60,67,73,77,91136, 45, 59, 60, 67, 73, 77, 911.\newlineAn outlier is a data point that is significantly different from the rest of the data. In this case, 911911 is much larger than all other numbers and stands out as the outlier.
  2. Calculate Mean Without Outlier: Remove the outlier and calculate the mean of the remaining data.\newlineThe remaining data set after removing 911911 is: 3636, 4545, 5959, 6060, 6767, 7373, 7777.\newlineCalculate the sum of these numbers: 36+45+59+60+67+73+77=41736 + 45 + 59 + 60 + 67 + 73 + 77 = 417.\newlineCount the number of data points: There are 77 data points.\newlineCalculate the mean: Mean = Sum of data points / Number of data points = 363600 (rounded to two decimal places).
  3. Calculate Mean With Outlier: Calculate the mean of the original data set including the outlier.\newlineThe original data set is: 36,45,59,60,67,73,77,91136, 45, 59, 60, 67, 73, 77, 911.\newlineCalculate the sum of these numbers: 36+45+59+60+67+73+77+911=132836 + 45 + 59 + 60 + 67 + 73 + 77 + 911 = 1328.\newlineCount the number of data points: There are 88 data points.\newlineCalculate the mean: Mean = Sum of data points / Number of data points = 1328/8=1661328 / 8 = 166.
  4. Compare Mean Changes: Compare the means to determine if the mean would increase or decrease upon removal of the outlier. The mean of the original data set with the outlier is 166166. The mean of the data set without the outlier is approximately 59.5759.57. Since the mean without the outlier is less than the mean with the outlier, removing the outlier would decrease the mean.

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