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Select the outlier in the data set.\newline33,43,57,67,69,74,80,19133, 43, 57, 67, 69, 74, 80, 191\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline33,43,57,67,69,74,80,19133, 43, 57, 67, 69, 74, 80, 191\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 33,43,57,67,69,74,80,19133, 43, 57, 67, 69, 74, 80, 191\newlineTo find the outlier, look for a number that is significantly different from the rest.\newlineOutlier: 191191, as it is much higher than the other numbers.
  2. Calculate Mean: Step 22: Calculate the mean of the original data set.\newlineMean = (33+43+57+67+69+74+80+191)/8(33 + 43 + 57 + 67 + 69 + 74 + 80 + 191) / 8\newlineMean = 614/8614 / 8\newlineMean = 76.7576.75
  3. Remove Outlier: Step 33: Remove the outlier and calculate the new mean.\newlineNew data set: 33,43,57,67,69,74,8033, 43, 57, 67, 69, 74, 80\newlineNew mean =(33+43+57+67+69+74+80)/7= (33 + 43 + 57 + 67 + 69 + 74 + 80) / 7\newlineNew mean =423/7= 423 / 7\newlineNew mean =60.43= 60.43
  4. Compare Means: Step 44: Compare the original mean and the new mean to determine if the mean increased or decreased.\newlineOriginal mean: 76.7576.75\newlineNew mean: 60.4360.43\newlineSince the new mean is less than the original mean, the mean decreases when the outlier is removed.

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