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Select the outlier in the data set.\newline33,43,47,56,64,77,80,90,96633, 43, 47, 56, 64, 77, 80, 90, 966\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline33,43,47,56,64,77,80,90,96633, 43, 47, 56, 64, 77, 80, 90, 966\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 33,43,47,56,64,77,80,90,96633, 43, 47, 56, 64, 77, 80, 90, 966\newlineTo find the outlier, look for a number that is significantly different from the rest.\newlineOutlier: 966966
  2. Calculate Mean with Outlier: Step 22: Calculate the mean of the data set including the outlier.\newlineMean = (33+43+47+56+64+77+80+90+966)/9(33 + 43 + 47 + 56 + 64 + 77 + 80 + 90 + 966) / 9\newlineMean = 1456/91456 / 9\newlineMean = 161.78161.78
  3. Calculate Mean without Outlier: Step 33: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (33+43+47+56+64+77+80+90)/8(33 + 43 + 47 + 56 + 64 + 77 + 80 + 90) / 8\newlineMean without outlier = 490/8490 / 8\newlineMean without outlier = 61.2561.25
  4. Compare Mean Changes: Step 44: Compare the two means to determine if the mean increases or decreases when the outlier is removed.\newlineMean with outlier = 161.78161.78\newlineMean without outlier = 61.2561.25\newlineSince 161.78 > 61.25, removing the outlier decreases the mean.

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