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Select the outlier in the data set.\newline3,75,79,80,81,95,97,993, 75, 79, 80, 81, 95, 97, 99\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline3,75,79,80,81,95,97,993, 75, 79, 80, 81, 95, 97, 99\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set: 3,75,79,80,81,95,97,993, 75, 79, 80, 81, 95, 97, 99. To find the outlier, we can look for a number that is significantly different from the rest of the data. In this case, 33 is much lower than all other numbers, which are all 7575 or higher.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included: (3+75+79+80+81+95+97+99)/8(3 + 75 + 79 + 80 + 81 + 95 + 97 + 99) / 8. Perform the calculation: 3+75+79+80+81+95+97+99=6093 + 75 + 79 + 80 + 81 + 95 + 97 + 99 = 609. Now divide by 88: 609/8=76.125609 / 8 = 76.125.
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier: (75+79+80+81+95+97+99)/7(75 + 79 + 80 + 81 + 95 + 97 + 99) / 7. Perform the calculation: 75+79+80+81+95+97+99=60675 + 79 + 80 + 81 + 95 + 97 + 99 = 606. Now divide by 77: 606/7=86.57142857142857606 / 7 = 86.57142857142857.
  4. Compare Means: Compare the two means to determine if the mean would increase or decrease with the removal of the outlier. The mean with the outlier is 76.12576.125, and the mean without the outlier is 86.5714285714285786.57142857142857. Since the mean without the outlier is higher, removing the outlier would increase the mean.

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