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Select the outlier in the data set.\newline3,74,78,79,84,85,86,90,943, 74, 78, 79, 84, 85, 86, 90, 94\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline3,74,78,79,84,85,86,90,943, 74, 78, 79, 84, 85, 86, 90, 94\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set: 3,74,78,79,84,85,86,90,943, 74, 78, 79, 84, 85, 86, 90, 94. An outlier is a data point that is significantly different from the rest of the data. We can often spot an outlier by looking for a number that seems much lower or higher than the rest of the data set.
  2. Spot Outlier: Looking at the data set, 33 is much lower than all other numbers, which are all 7474 or higher. Therefore, 33 is the outlier in this data set.
  3. Calculate Mean Original: Calculate the mean of the original data set including the outlier.\newlineMean = (3+74+78+79+84+85+86+90+94)/9(3 + 74 + 78 + 79 + 84 + 85 + 86 + 90 + 94) / 9\newlineMean = (673)/9(673) / 9\newlineMean ≈74.78\approx 74.78
  4. Calculate Mean Without Outlier: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (74+78+79+84+85+86+90+94)/8(74 + 78 + 79 + 84 + 85 + 86 + 90 + 94) / 8\newlineMean without outlier = (670)/8(670) / 8\newlineMean without outlier ≈83.75\approx 83.75
  5. Compare Means: Compare the two means to determine if the mean would increase or decrease upon the removal of the outlier. The mean without the outlier (83.7583.75) is greater than the mean with the outlier (74.7874.78). Therefore, the mean would increase if the outlier were removed.

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