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Select the outlier in the data set.\newline3,40,44,47,48,49,51,53,593, 40, 44, 47, 48, 49, 51, 53, 59\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline3,40,44,47,48,49,51,53,593, 40, 44, 47, 48, 49, 51, 53, 59\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set: 3,40,44,47,48,49,51,53,593, 40, 44, 47, 48, 49, 51, 53, 59. An outlier is a data point that is significantly different from the rest of the data. We can often spot an outlier by looking for a number that is much smaller or larger than the rest.
  2. Spot Outlier: Looking at the data set, we can see that the number 33 is much smaller than all other numbers, which are all 4040 or higher. Therefore, 33 is the outlier in this data set.
  3. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included:\newlineMean = (3+40+44+47+48+49+51+53+59)/9(3 + 40 + 44 + 47 + 48 + 49 + 51 + 53 + 59) / 9\newlineMean = 394/9394 / 9\newlineMean ≈43.78\approx 43.78
  4. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier:\newlineMean = (40+44+47+48+49+51+53+59)/8(40 + 44 + 47 + 48 + 49 + 51 + 53 + 59) / 8\newlineMean = 391/8391 / 8\newlineMean ≈48.88\approx 48.88
  5. Compare Means: Compare the two means to determine if the mean would increase or decrease with the removal of the outlier:\newlineThe mean without the outlier (≈48.88\approx 48.88) is greater than the mean with the outlier (≈43.78\approx 43.78). Therefore, removing the outlier would increase the mean.

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