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Select the outlier in the data set.\newline26,36,38,49,57,59,60,78,59626, 36, 38, 49, 57, 59, 60, 78, 596\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline26,36,38,49,57,59,60,78,59626, 36, 38, 49, 57, 59, 60, 78, 596\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 26,36,38,49,57,59,60,78,59626, 36, 38, 49, 57, 59, 60, 78, 596\newlineTo find the outlier, look for a number that is significantly different from the rest. Here, 596596 stands out as it is much higher than the other numbers.
  2. Calculate Mean with Outlier: Step 22: Calculate the mean of the data set including the outlier.\newlineMean = (26+36+38+49+57+59+60+78+596)/9(26 + 36 + 38 + 49 + 57 + 59 + 60 + 78 + 596) / 9\newlineMean = 999/9999 / 9\newlineMean = 111111
  3. Calculate Mean without Outlier: Step 33: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (26+36+38+49+57+59+60+78)/8(26 + 36 + 38 + 49 + 57 + 59 + 60 + 78) / 8\newlineMean without outlier = 403/8403 / 8\newlineMean without outlier = 50.37550.375
  4. Compare Mean Changes: Step 44: Compare the two means to determine if the mean increases or decreases when the outlier is removed.\newlineOriginal mean = 111111\newlineMean without outlier = 50.37550.375\newlineSince 50.37550.375 is less than 111111, removing the outlier decreases the mean.

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