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Select the outlier in the data set.\newline22,32,50,56,63,66,87,93,49422, 32, 50, 56, 63, 66, 87, 93, 494\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline22,32,50,56,63,66,87,93,49422, 32, 50, 56, 63, 66, 87, 93, 494\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set.\newlineThe data set is: 22,32,50,56,63,66,87,93,49422, 32, 50, 56, 63, 66, 87, 93, 494\newlineAn outlier is a data point that is significantly different from the rest of the data. In this case, 494494 is much larger than all other numbers in the set, so it is the outlier.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included.\newlineMean = (Sum of all data points) / (Number of data points)\newlineMean = (22+32+50+56+63+66+87+93+494)/9(22 + 32 + 50 + 56 + 63 + 66 + 87 + 93 + 494) / 9\newlineMean = (963)/9(963) / 9\newlineMean = 107107
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (Sum of all data pointsOutlier)/(Number of data points1)(\text{Sum of all data points} - \text{Outlier}) / (\text{Number of data points} - 1)\newlineMean without outlier = (963494)/(91)(963 - 494) / (9 - 1)\newlineMean without outlier = (469)/8(469) / 8\newlineMean without outlier = 58.62558.625
  4. Compare Mean Changes: Compare the two means to determine if the mean would increase or decrease upon the removal of the outlier. The mean with the outlier is 107107, and the mean without the outlier is 58.62558.625. Removing the outlier significantly decreases the mean.

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